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2016 Oct cisco ccnp routing/switching 300-101 route:

Q71. A network engineer is trying to implement broadcast-based NTP in a network and executes the ntp broadcast client command. Assuming that an NTP server is already set up, what is the result of the command? 

A. It enables receiving NTP broadcasts on the interface where the command was executed. 

B. It enables receiving NTP broadcasts on all interfaces globally. 

C. It enables a device to be an NTP peer to another device. 

D. It enables a device to receive NTP broadcast and unicast packets. 

Answer: A 

Explanation: 

The NTP service can be activated by entering any ntp command. When you use the ntp broadcast client

command, the NTP service is activated (if it has not already been activated) and the device is configured to receive NTP broadcast packets on a specified interface simultaneously.

Command Description

ntp broadcast Allows the system to receive NTP broadcast packets on an client interface.

Reference: http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/bsm/command/bsm-xe-3se-3850- cr-book/

bsm-xe-3se-3850-cr-book_chapter_00.html


Q72. A network engineer is trying to modify an existing active NAT configuration on an IOS router by using the following command: 

(config)# no ip nat pool dynamic-nat-pool 192.1.1.20 192.1.1.254 netmask 255.255.255.0 

Upon entering the command on the IOS router, the following message is seen on the console: 

%Dynamic Mapping in Use, Cannot remove message or the %Pool outpool in use, cannot destroy 

What is the least impactful method that the engineer can use to modify the existing IP NAT configuration? 

A. Clear the IP NAT translations using the clear ip nat traffic * " command, then replace the NAT configuration quickly, before any new NAT entries are populated into the translation table due to active NAT traffic. 

B. Clear the IP NAT translations using the clear ip nat translation * " command, then replace the NAT configuration quickly, before any new NAT entries are populated into the translation table due to active NAT traffic. 

C. Clear the IP NAT translations using the reload command on the router, then replace the NAT configuration quickly, before any new NAT entries are populated into the translation table due to active NAT traffic. 

D. Clear the IP NAT translations using the clear ip nat table * " command, then replace the NAT configuration quickly, before any new NAT entries are populated into the translation table due to active NAT traffic. 

Answer: B 

Explanation: 


Q73. CORRECT TEXT 

JS Industries has expanded their business with the addition of their first remote office. The remote office router (R3) was previously configured and all corporate subnets were reachable from R3. JS Industries is interested in using route summarization along with the EIGRP Stub Routing feature to increase network stability while reducing the memory usage and bandwidth utilization to R3. Another network professional was tasked with implementing this solution. However, in the process of configuring EIGRP stub routing connectivity with the remote network devices off of R3 has been lost. 

Currently EIGRP is configured on all routers R2, R3, and R4 in the network. Your task is to identify and resolve the cause of connectivity failure with the remote office router R3. Once the issue has been resolved you should complete the task by configuring route summarization only to the remote office router R3. 

You have corrected the fault when pings from R2 to the R3 LAN interface are successful, and the R3 IP routing table only contains 2 10.0.0.0 subnets. 





Answer: Here are the solution as below: 

Explanation: 

First we have to figure out why R3 and R4 can not communicate with each other. Use the show running-config command on router R3. 


Notice that R3 is configured as a stub receive-only router. The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system. This keyword will also prevent any type of route from being sent. Therefore we will remove this command and replace it with the eigrp stub command: 

R3# configure terminal 

R3(config)# router eigrp 123 

R3(config-router)# no eigrp stub receive-only 

R3(config-router)# eigrp stub 

R3(config-router)# end 

Now R3 will send updates containing its connected and summary routes to other routers. Notice that the eigrp stub command equals to the eigrp stub connected summary because the connected and summary options are enabled by default. Next we will configure router R3 so that it has only 2 subnets of 10.0.0.0 network. Use the show ip route command on R3 to view its routing table: 


Because we want the routing table of R3 only have 2 subnets so we have to summary sub-networks at the interface which is connected with R3, the s0/0 interface of R4. 

There is one interesting thing about the output of the show ip route shown above: the 10.2.3.0/24, which is a directly connected network of R3. We can’t get rid of it in the routing table no matter what technique we use to summary the networks. Therefore, to make the routing table of R3 has only 2 subnets we have to summary other subnets into one subnet. 

In the output if we don’t see the summary line (like 10.0.0.0/8 is a summary…) then we should use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 so that all the ping can work well. 

In conclusion, we will use the ip summary-address eigrp 123 10.2.0.0 255.255.0.0 at the interface s0/0 of R4 to summary. 

R4> enable 

R4# conf t 

R4(config)# interface s0/0 

R4(config-if)# ip summary-address eigrp 123 10.2.0.0 255.255.0.0 

Now we jump back to R3 and use the show ip route command to verify the effect, the output is shown below: 


Note: Please notice that the IP addresses and the subnet masks in your real exam might be different so you might use different ones to solve this question. Just for your information, notice that if you use another network than 10.0.0.0/8 to summary, for example, if you use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 you will leave a /16 network in the output of the show ip route command. 


But in your real exam, if you don’t see the line "10.0.0.0/8 is a summary, Null0" then you can summarize using the network 10.2.0.0/16. This summarization is better because all the pings can work well. Finally don’t forget to use the copy run start command on routers R3 and R4 to save the configurations. R3(config-if)# end R3# copy run start R4(config-if)# end R4# copy run start 

If the “copy run start” command doesn’t work then use “write memory.” 


Up to date 300-101 practice exam:

Q74. Two aspects of an IP SLA operation can be tracked: state and reachability. Which statement about state tracking is true? 

A. When tracking state, an OK return code means that the track's state is up; any other return code means that the track's state is down. 

B. When tracking state, an OK or over threshold return code means that the track's state is up; any other return code means that the track's state is down. 

C. When tracking state, an OK return code means that the track's state is down; any other return code means that the track's state is up. 

D. When tracking state, an OK or over threshold return code means that the track's state is down; any other return code means that the track's state is up. 

Answer: A 

Explanation: 


Q75. Which three problems result from application mixing of UDP and TCP streams within a network with no QoS? (Choose three.) 

A. starvation 

B. jitter 

C. latency 

D. windowing 

E. lower throughput 

Answer: A,C,E 

Explanation: 

It is a general best practice not to mix TCP-based traffic with UDP-based traffic (especially

streaming video) within a single service provider class due to the behaviors of these protocols during

periods of congestion. Specifically, TCP transmitters will throttle-back flows when drops have been

detected. Although some UDP applications have application-level windowing, flow control, and

retransmission capabilities, most UDP transmitters are completely oblivious to drops and thus never lower

transmission rates due to dropping. When TCP flows are combined with UDP flows in a single service

provider class and the class experiences congestion, then TCP flows will continually lower their rates,

potentially giving up their bandwidth to drop-oblivious UDP flows. This effect is called TCP-starvation/

UDP-dominance. This can increase latency and lower the overall throughput. TCP-starvation/UDPdominance

likely occurs if (TCP-based) mission-critical data is assigned to the same service provider class

as (UDP-based) streaming video and the class experiences sustained congestion. Even if WRED is

enabled on the service provider class, the same behavior would be observed, as WRED (for the most part)

only affects TCP-based flows. Granted, it is not always possible to separate TCP-based flows from UDPbased

flows, but it is beneficial to be aware of this behavior when making such application-mixing

decisions. Reference: http://www.cisco.com/warp/public/cc/so/neso/vpn/vpnsp/spqsd_wp.htm


Q76. A network administrator uses IP SLA to measure UDP performance and notices that packets on one router have a higher one-way delay compared to the opposite direction. Which UDP characteristic does this scenario describe? 

A. latency 

B. starvation 

C. connectionless communication 

D. nonsequencing unordered packets 

E. jitter 

Answer: A 

Explanation: 

Cisco IOS IP SLAs provides a proactive notification feature with an SNMP trap. Each measurement

operation can monitor against a pre-set performance threshold.

Cisco IOS IP SLAs generates an SNMP trap to alert management applications if this threshold is crossed.

Several SNMP traps are available: round trip time, average jitter, one-way latency, jitter, packet loss, MOS, and connectivity tests.

Here is a partial sample output from the IP SLA statistics that can be seen:

router#show ip sla statistics 1

Round Trip Time (RTT) for Index 55

Latest RTT: 1 ms

Latest operation start time: *23:43:31.845 UTC Thu Feb 3 2005 Latest operation return code: OK

RTT Values:

Number Of RTT: 10 RTT Min/Avg/Max: 1/1/1 milliseconds Latency one-way time:

Number of Latency one-way Samples: 0

Source to Destination Latency one way Min/Avg/Max: 0/0/0 milliseconds Destination to Source Latency

one way Min/Avg/Max: 0/0/0 milliseconds 

Reference:

http://www.cisco.com/en/US/technologies/tk648/tk362/tk920/technologies_white_paper09186a0

0802d5efe.html


Q77. An engineer has configured a router to use EUI-64, and was asked to document the IPv6 address of the router. The router has the following interface parameters: 

mac address C601.420F.0007 

subnet 2001:DB8:0:1::/64 

Which IPv6 addresses should the engineer add to the documentation? 

A. 2001:DB8:0:1:C601:42FF:FE0F:7 

B. 2001:DB8:0:1:FFFF:C601:420F:7 

C. 2001:DB8:0:1:FE80:C601:420F:7 

D. 2001:DB8:0:1:C601:42FE:800F:7 

Answer: A 

Explanation: 

Explanation: Extended Unique Identifier (EUI), as per RFC2373, allows a host to assign iteslf a unique 64-

Bit IP Version 6 interface identifier (EUI-64). This feature is a key benefit over IPv4 as it eliminates the

need of manual configuration or DHCP as in the world of IPv4. The IPv6 EUI-64 format address is obtained

through the 48-bit MAC address. The Mac address is first separated into two 24-bits, with one being OUI

(Organizationally Unique Identifier) and the other being NIC specific. The 16-bit 0xFFFE is then inserted

between these two 24-bits to for the 64-bit EUI address. IEEE has chosen FFFE as a reserved value which

can only appear in EUI-64 generated from the EUI-48 MAC address. Here is an example showing how the

Mac Address is used to generate EUI.


Next, the seventh bit from the left, or the universal/local (U/L) bit, needs to be inverted. This bit identifies

whether this interface identifier is universally or locally administered. If 0, the address is locally

administered and if 1, the address is globally unique. It is worth noticing that in the OUI portion, the globally

unique addresses assigned by the IEEE has always been set to 0 whereas the locally created addresses

has 1 configured. Therefore, when the bit is inverted, it maintains its original scope (global unique address

is still global unique and vice versa). The reason for inverting can be found in RFC4291 section 2.5.1.

Reference: https:// supportforums.cisco.com/document/100566/understanding-ipv6-eui-64-bit- address